# CALCULO EN VARIEDADES SPIVAK PDF Author: Malaran Kigazuru Country: Venezuela Language: English (Spanish) Genre: Photos Published (Last): 15 February 2018 Pages: 222 PDF File Size: 9.27 Mb ePub File Size: 9.70 Mb ISBN: 708-4-20545-413-2 Downloads: 58898 Price: Free* [*Free Regsitration Required] Uploader: Vudokree For the converse, suppose that is angle preserving. Let be norm preserving. Since is a linear map of a finite dimensional vector space into itself, it follows that is also onto. Parte 1 de If and are continuous, then the assertion is true.

### Calculo En Variedades/ Calculus of Variations: Michael Spivak: Books –

The angle preserving are precisely those which can be expressed in the form vqriedades U is angle preserving of the kind in part bV is norm preserving, and the operation is functional composition. The linear transformation is angle preserving if is and for1.

Further, giventhere is a withand so. If for some realthen substituting back into the equality shows that must be non-positive or must be 0. Define to be the linear transformation such that is angle preserving, the are also pairwise orthogonal. This is a consequence of the analogous assertion of the next problem. The transformation is by Cramer’s Rule because the determinant of its matrix is 1.

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Trabalho do Professor Shing Tung Yau. If there is a basis of and numbers such thatprove that is angle preserving if and only if all are equal. On the other hand, ifthen the result follows The inequality follows from Theorem Let be an orthogonal basis of. To correct the situation, add the condition that the be pairwise orthogonal, because all the cross terms are zero.

In particular, has an inverse. This completes the characterization. Further, is norm splvak since. Show that is norm preserving if and only if is inner product preserving. Geometrically, if, and are the vertices of a triangle, then the inequality says that the length of a side is no larger than the sum of the lengths of the other two sides.

Clearly, any of this form is angle preserving as the composition of two angle preserving linear transformations is angle preserving. Then part a gives the inequality of Theorem 2.

## Calculo En Variedades/ Calculus of Variations

Further, maps each to a scalar multiple of itself; so is a map of the type in part b. A linear transformation is called norm preserving if1. In fact, suppose that for eachthere is an with. If for some realthen substituting shows that the inequality is equivalent to and clearly equality holds if a is non.

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Note, however, that the equality condition does not follow from a. So T is Then the inequality holds true in an open neighborhood of since and are. Similarly, if is norm preserving, then the polarization identity together with the linearity of T give:. Equality holds precisely when one is a nonnegative multiple of the other.

So since the integrand is always non-negative it must be that its discriminant is negative. Prove that if is norm preserving, then is angle preserving. I claim that equality holds precisely when one vector is a non-positive multiple of the other. No, you could, for example, vary at discrete points without changing the values of the integrals. So, this condition suffices to make be angle preserving. Then impliesi. The case where is treated similarly. If and in are both non-zero, then the angle between anddenotedis defined to be which makes sense by Theorem 2. The first assertion is the triangle inequality.